For the reaction,

$SO subscript 2 space left parenthesis straight g right parenthesis space plus space 1 half space straight O subscript 2 space left parenthesis straight g right parenthesis space leftwards harpoon over rightwards harpoon space SO subscript 3 space left parenthesis straight g right parenthesis$
if K_p = K_c (RT)^x where the symbol has usual meaning then the value of x is (assuming ideality)

-1

-1/2

1/2

1

Solution

-1/2

For the given reaction, ∆n_g = n_p-n_R
where n_p = number of moles of products
nR = number of moles of reactants
Kp = K_c (RT)^∆n_g
∆n_g = -1/2

Some More Questions From Equilibrium Chapter

For Daily Free Study Material Join wiredfaculty