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Some Basic Concepts Of Chemistry

Question
CBSEENCH11008058
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In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of AgBr. The percentage of bromine in the compound is: (at. Mass Ag = 108; Br = 80)

  • 24

  • 36

  • 48

  • 60

Solution

A.

24

Weight of Organic compound = 250 mg
Weight of AgBr = 141 mg
therefore, According to the formula of % of bromine by Carius method
percent sign space of space Br space equals space fraction numerator Atomic space weight space of space Br over denominator Molecular space weight space of space AgBr end fraction space space space space space space space space space space space space space space space straight x space fraction numerator weight space of space AgBr over denominator Weight space of space organic space bromide end fraction straight x 100 therefore percent sign space of space Br space equals space 80 over 188 space straight x space 141 over 250 space straight x 100 space equals space 1128000 over 47000 space equals space 24 space percent sign

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