Some Basic Concepts Of Chemistry

  • Question
    CBSEENCH11008058

    In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of AgBr. The percentage of bromine in the compound is: (at. Mass Ag = 108; Br = 80)

    • 24

    • 36

    • 48

    • 60

    Solution

    A.

    24

    Weight of Organic compound = 250 mg
    Weight of AgBr = 141 mg
    therefore, According to the formula of % of bromine by Carius method
    percent sign space of space Br space equals space fraction numerator Atomic space weight space of space Br over denominator Molecular space weight space of space AgBr end fraction space
space space space space space space space space space space space space space space straight x space fraction numerator weight space of space AgBr over denominator Weight space of space organic space bromide end fraction straight x 100
therefore percent sign space of space Br space equals space 80 over 188 space straight x space 141 over 250 space straight x 100
space equals space 1128000 over 47000 space equals space 24 space percent sign

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