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Redox Reactions

Question
CBSEENCH11006779

The Mn3+ ions is unstable in solution and undergoes disproportionation to give Mn2+MnO2 and H+ ion. Write a balanced ionic equation for the reaction.

Solution

The skeleton equation is
Mn3+ (aq) → Mn2+ (aq) + MnO2(s) + H+(aq)
Let us balance the above equation by ion electron method.
1. Write the oxidation and reduction half-reactions by observing the changes in oxidation number and writing these separately
Oxidation half-reaction:
            +3                    +4
            Mn to the power of 3 plus end exponent left parenthesis aq right parenthesis space space rightwards arrow space space space space space MnO subscript 2 left parenthesis straight s right parenthesis
  Reduction half reaction:
             +3                         +2
             Mn to the power of 3 plus end exponent space left parenthesis aq right parenthesis space space space space space rightwards arrow space space space space Mn to the power of 2 plus end exponent left parenthesis aq right parenthesis

2. Balancing the oxidation half reaction
(i) Add 1 electron towards R.H.S. to balance the charge on Mn.
                  Mn to the power of 3 plus end exponent left parenthesis aq right parenthesis space rightwards arrow space space space MnO subscript 2 left parenthesis straight s right parenthesis space plus straight e to the power of minus
(ii) Balance the charges by adding four H+ towards R.H.S.
               Mn to the power of 3 plus end exponent left parenthesis aq right parenthesis space space rightwards arrow space space space MnO subscript 2 left parenthesis straight s right parenthesis space plus space 4 straight H to the power of plus left parenthesis aq right parenthesis space plus straight e to the power of minus
                               [Balanced oxidation half reaction]
(iii) Balance O atoms by adding two H2O molecules downwards L.H.S.
          Mn to the power of 3 plus end exponent left parenthesis aq right parenthesis space plus 2 straight H subscript 2 straight O left parenthesis straight l right parenthesis space space rightwards arrow space space MnO subscript 2 left parenthesis straight s right parenthesis space plus space 4 straight H to the power of plus left parenthesis aq right parenthesis space plus straight e to the power of minus
                              [Balanced oxidation half reaction]
3. Balancing the reduction half reaction:
         Add 1 electron towards L.H.S. to balance the charge on Mn. 
                   Mn to the power of 3 plus end exponent left parenthesis aq right parenthesis space plus space straight e to the power of minus space space rightwards arrow space space space space Mn to the power of 2 plus end exponent left parenthesis aq right parenthesis
                                   (Balanced reduction half reaction]
4. Adding balanced oxidation half reaction and balanced reduction half-reaction. 
                     2 Mn to the power of 3 plus end exponent left parenthesis aq right parenthesis space plus space 2 straight H subscript 2 straight O left parenthesis straight l right parenthesis space space rightwards arrow space space MnO subscript 2 left parenthesis straight s right parenthesis space plus space Mn to the power of 2 plus end exponent left parenthesis aq right parenthesis space plus space 4 straight H to the power of plus left parenthesis aq right parenthesis
This is balanced redox equation for disproportionation reaction.