Question
Balance the following equation by half reaction method in acidic medium:
Solution
(i) Write the oxidation and reduction half-reactions by observing the changes in oxidation numbers and write these separately.
-1 0
oxidation half reaction: Br-
Br2
Reduction half-reaction:

2. Balancing the oxidation half reaction.
(i) Balance Br atoms by multiplying Br- by 2.

(ii) Add 2 electrons towards R.H.S. in order to balance the charges on bromine atoms.

3. Balancing the reduction half reaction.
(i) Balancing of Mn is not required as the number of each Mn is one on both the sides.

(ii) Add 5 electrons towards L.H.S. in order to balance the charge on manganese atoms.

(iii) Balance H atoms by adding 8H+ towards
L.H.S.

4. Multiply balanced oxidation half-reaction by 5 and balanced reduction half-reaction by 2 to equate electrons and add both the half reactions.

This is a balanced redox equation.
-1 0
oxidation half reaction: Br-

Reduction half-reaction:

2. Balancing the oxidation half reaction.
(i) Balance Br atoms by multiplying Br- by 2.

(ii) Add 2 electrons towards R.H.S. in order to balance the charges on bromine atoms.

3. Balancing the reduction half reaction.
(i) Balancing of Mn is not required as the number of each Mn is one on both the sides.

(ii) Add 5 electrons towards L.H.S. in order to balance the charge on manganese atoms.

(iii) Balance H atoms by adding 8H+ towards
L.H.S.

4. Multiply balanced oxidation half-reaction by 5 and balanced reduction half-reaction by 2 to equate electrons and add both the half reactions.

This is a balanced redox equation.