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Redox Reactions

Question
CBSEENCH11006765

Balance the following chemical equation by oxidation number method:
          Zn space plus space NO subscript 3 superscript minus space space rightwards arrow space space space Zn to the power of 2 plus end exponent space plus space left parenthesis NH subscript 4 right parenthesis to the power of plus in acidic medium.

Solution

(i) The skeleton equation along with oxidation number of each atom is
 Zn space equals space space space space space open square brackets NO subscript 3 close square brackets to the power of minus space space space space rightwards arrow space space space space open square brackets Zn close square brackets to the power of 2 plus end exponent space plus space open square brackets NH subscript 4 close square brackets to the power of plus
left parenthesis Zn space equals 0 right parenthesis space space left parenthesis straight N space equals plus 5 right parenthesis space space space left parenthesis Zn space equals space plus 2 right parenthesis thin space left parenthesis straight N space equals space minus 3 right parenthesis
 
(ii) Noting the change in O.N. of above atoms
Increase Zn = 0 to  +2  i.e 2
Decrease N = +5 to -3 i.e. 8
(iii) Equalise the increase/decrease O.N. by multiplying Zn by 4 and NO subscript 3 superscript minus by 1.
                4 Zn space plus space left parenthesis NO subscript 3 superscript minus right parenthesis space space space rightwards arrow space space space space Zn to the power of 2 plus end exponent space plus space left parenthesis NH subscript 4 right parenthesis to the power of plus
(iv) Balance Zn atoms by multiple Zn2 ion by 4.
    4 Zn plus left parenthesis NO subscript 3 right parenthesis to the power of minus space space space rightwards arrow space space space space 4 Zn to the power of 2 plus end exponent space plus space left parenthesis NH subscript 4 right parenthesis to the power of plus
(v) Balance the oxygen atoms by adding three H2O molecules on the right-hand side. 
4 Zn plus left parenthesis NO subscript 3 right parenthesis to the power of minus space space space rightwards arrow space space space 4 Zn to the power of 2 plus end exponent space plus space left parenthesis NH subscript 4 right parenthesis to the power of plus space plus space 3 straight H subscript 2 straight O
(vi) Balancing the hydrogen atoms by adding 10H+ ions  on the reactant side. The complete balanced equation is
4 Zn space plus space left parenthesis NO subscript 3 right parenthesis to the power of minus space plus space 10 straight H to the power of plus space space rightwards arrow space space space 4 Zn to the power of 2 plus end exponent space plus space left parenthesis NH subscript 4 right parenthesis to the power of plus space plus space 3 straight H subscript 2 straight O