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Redox Reactions

Question
CBSEENCH11006764
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Balance the following,chemical equation by oxidation number method:

Mn to the power of 2 plus end exponent space plus space straight S subscript 2 straight O subscript 8 superscript 2 minus end superscript space space space space rightwards arrow space space space space stack MnO subscript 4 superscript minus space plus space HSO subscript 4 superscript minus with left parenthesis acidic space medium right parenthesis below

Solution
(i)The skeleton equation along with oxidation number each atom is:
space space straight O. straight N space increases space by space 5 space per space atom stack Mn to the power of 2 plus end exponent with Mn equals plus 2 below and plus 2 on top space space plus stack stack left square bracket straight S subscript 2 with plus 7 on top space stack straight O subscript 8 with negative 2 on top with straight S equals plus 7 below right square bracket to the power of 2 minus end exponent space rightwards arrow space stack Mn with plus 7 on top space straight O with negative 2 on top to the power of negative space end exponent with Mn space equals plus 7 below space space space plus space stack straight H with plus 1 on top straight S with plus 6 on top space stack straight O subscript 4 superscript minus with negative 2 on top with straight S equals space plus 6 below ii right parenthesis space Equalise space the space increase space divided by decrease space in space straight O. straight N. space multiply space Mn to the power of 2 plus end exponent by space 2 space and space 5 straight S subscript 2 straight O subscript 8 superscript 2 minus end superscript space by space 5 comma 2 Mn to the power of 2 plus end exponent space plus space space 5 straight S subscript 2 straight O subscript 8 superscript 2 minus end superscript space rightwards arrow space MnO subscript 4 superscript minus space plus HSO subscript 4 superscript minus iii right parenthesis space Balance space straight O space atoms comma space by space adding space eight space straight H subscript 2 straight O space molecules space on space the space reactant space side comma 2 Mn to the power of 2 plus end exponent space plus 5 straight S subscript 2 straight O subscript 8 superscript 2 minus end superscript space space plus 8 straight H subscript 2 straight O space rightwards arrow space 2 MnO subscript 4 superscript minus space plus space 10 HSO subscript 4 superscript minus Balance space the space straight H space atoms comma Net space charge space on space LHS space equals plus 4 minus 10 space equals negative 6 Net space charge space on space RHS space equals negative 2 minus 10 space equals negative 12 Adding space six space straight H to the power of plus space on space RHS comma 2 Mn to the power of 2 plus end exponent space plus 5 straight S subscript 2 straight O subscript 8 superscript 2 minus end superscript space plus 8 straight H subscript 2 straight O space rightwards arrow space space space space space space space space space space space space space space space space space space 2 MnO subscript 4 superscript minus space plus space 10 space HSO subscript 4 superscript minus space plus 6 straight H to the power of plus

Some More Questions From Redox Reactions Chapter

Can oxidation occur without reduction?

What are redox reactions?

What are direct redox reactions? Give one example.

What are indirect redox reactions?

Write formulas for the following compounds:
(a) Mercury (II) chloride
(b) Nickel (II) sulphate
(c) Tin (IV) oxide
(d) Thallium (I) sulphate
(e) Iron (III) sulphate
(f) Chromium (III) oxide

What are electrolytes?

What are cations and anions?

What is electrolysis?

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