Question
Balance the euqation by oxidation number method:
Solution
1. The skeleton equation.along with oxidation number of each atom is
+ 1 + 1 0 +4 -2 +1 -2
C6H6 + O2
C O2 +H2 O
(C =-1) (O =0) (C= +4) (O = -2)
2. The oxidation number of C increases from to +4, while that of oxygen decreases from. 0 to -2 (in H2O). Therefore, the equation may be? written
3. Equalise the increase/decrease in O.N. by multiplying C6H6 by 2 and O2 by 15, we get,
4. On counting and balancing the atoms on both the sides, we get the balanced equation as
+ 1 + 1 0 +4 -2 +1 -2
C6H6 + O2
C O2 +H2 O(C =-1) (O =0) (C= +4) (O = -2)
2. The oxidation number of C increases from to +4, while that of oxygen decreases from. 0 to -2 (in H2O). Therefore, the equation may be? written
3. Equalise the increase/decrease in O.N. by multiplying C6H6 by 2 and O2 by 15, we get,
4. On counting and balancing the atoms on both the sides, we get the balanced equation as
