Question
Calculate the oxidation number of Fe in K4|Fe(CN)6|.
Solution
Let the oxidation number of Fe =x Writing the oxidation number of each atom at the top of its symbol.
+1 x -1
K4 [Fe(CN)6]
The algebraic sum of the oxidation number of various atoms = 0
4(+1) + x + 6(-1) = 0
or x - 2 = 0
or x = + 2
+1 x -1
K4 [Fe(CN)6]
The algebraic sum of the oxidation number of various atoms = 0
4(+1) + x + 6(-1) = 0
or x - 2 = 0
or x = + 2
