Assign oxidation number of the underlined elements in each of the following species:
$straight H subscript 4 bottom enclose straight P subscript 2 end enclose straight O subscript 7$

Solution

straight H subscript 4 bottom enclose straight P subscript 2 end enclose straight O subscript 7

Let the oxidation number of P = x
Writing the oxidation number of each atom at the top of its symbol.
+1 x - 2
H₄ P₂O₇Sum of the oxidation number of various atoms = 0
4(+1)+ 2x + 7(-2) = 0
i.e. x - 5 = 0
or x = +5

therefore space space space space Oxidation space number space of space straight P space in space straight H subscript 4 straight P subscript 2 straight O subscript 7 space equals space plus 5

Some More Questions From Redox Reactions Chapter

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Redox Reactions

Assign oxidation number of the underlined elements in each of the following species:
$straight H subscript 4 bottom enclose straight P subscript 2 end enclose straight O subscript 7$

Some More Questions From Redox Reactions Chapter

What is oxidation (electronic concept)?

What is reduction (electronic concept)?

What is reducing agent (electronic concept)?

What is an oxidising agent (electronic concept)?

Can oxidation occur without reduction?

What are redox reactions?

What are direct redox reactions? Give one example.

What are indirect redox reactions?

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