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Redox Reactions

Question
CBSEENCH11006736
Wired Faculty App

Determine the oxidation number of C in the following:

bold left parenthesis bold i bold right parenthesis bold space bold C subscript bold 2 bold H subscript bold 6 bold space bold space bold space bold space bold space bold space bold space bold space bold space bold left parenthesis bold ii bold right parenthesis bold space bold C subscript bold 4 bold H subscript bold 10 bold space bold space bold space bold space bold space bold space bold space bold space bold space bold left parenthesis bold iii bold right parenthesis bold space bold CO bold left parenthesis bold iv bold right parenthesis bold space bold CO subscript bold 2 bold space bold space bold space bold space bold space bold space bold space bold space space space


Solution

C2H6: Let the oxidation number of C= x
Oxidation number of H = 1
The algebraic sum of the oxidation number of various atoms = 0
       bold therefore bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold 2 bold x bold space bold plus bold space bold space bold 6 bold left parenthesis bold plus bold 1 bold right parenthesis bold space bold equals bold space bold 0 bold or bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold 2 bold x bold space bold space bold equals bold space bold minus bold 6 bold or bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold x bold space bold equals bold space bold space bold minus bold 3


(ii) C4H10:
 Let the oxidation number of C = x
Writing the oxidation number of each atom at the top of its symbol,
                           x                +1
                         C4                 H10
The algebraic sum of the oxidation number of various atoms = 0
 therefore                4x  + 10(+1) = 0
or                        4x = -10
or                         bold x bold space bold equals bold space bold minus bold 10 over bold 4 bold space bold equals bold minus bold 2 bold 1 over bold 2
(iii) CO:
Let the oxidation number of C = x
Writing the oxidation number of each atom at the top of its symbol,
                   x               -2
                   C                O
The algebraic sum of the oxidation number of various atoms = 0
                       therefore            x - 2  = 0
                        or             x = 2
(iv) CO2:
Let the oxidation number of C = x
Writing the oxidation number of each atom at the top of its symbol,
               x              -2
               C              O2
The algebraic sum of the oxidation number of various atoms = 0
therefore             x + 2(-2) = 0
or                  x = 4

                   
 

Some More Questions From Redox Reactions Chapter

Can oxidation occur without reduction?

What are redox reactions?

What are direct redox reactions? Give one example.

What are indirect redox reactions?

Write formulas for the following compounds:
(a) Mercury (II) chloride
(b) Nickel (II) sulphate
(c) Tin (IV) oxide
(d) Thallium (I) sulphate
(e) Iron (III) sulphate
(f) Chromium (III) oxide

What are electrolytes?

What are cations and anions?

What is electrolysis?

Mention two uses of electrolysis.

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