What are the changes which take place when a redox reaction is carried in a beaker? Explain with the help of a suitable example.
Or
Explain the redox reaction


occurring in a beaker.

When a zinc rod is placed in an aqueous solution of copper sulphate, the following changes will be observed:
(i) The zinc plate loses weight gradually.
(ii) A precipitate of copper settles at the bottom of the beaker.
(iii) The blue colour of the solution gradually fades.
(iv) The solution remains electrically neutral throughout.
(v) The solution becomes hot (exothermic reaction).
The overall reaction which takes place in a beaker may be represented as:

Here, Zn is oxidised to Zn²⁺ ions by losing two electrons and Cu²⁺ ions are reduced to Cu(s).
                          

As Cu²⁺ ions from the solution are changing to Cu(s), the blue colour of the solution which is due to Cu²⁺ ions, slowly fades. Also, the number of electrons lost in the oxidation half reaction is equal to the number of electrons gained in the reduction half reaction, the solution remains electrically neutral.
Similarly, when a copper rod is placed in a silver nitrate solution, silver gets precipitated with the evolution of heat energy. The reaction taking place in the beaker is:

Cancelling the common ion, 

Hence whenever a redox reaction is carried out in a single beaker, decrease in chemical energy or free energy appears in the form of heat.