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Equilibrium

Question
CBSEENCH11006609
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At a certain temperature, the solubility product of AgCl is 1 × 10–10, calculate the solubility of AgCl in g/litre.

Solution

Let the solubility of AgCl be S mole litre
AgCl space space space space space space rightwards harpoon over leftwards harpoon space space space space space space space space space space Ag to the power of plus space space space plus space space Cl to the power of minus straight S space mol space space space space space space space space space space space space space space space space space space straight S space mol space space space space space space space straight S space mol
Applying the law of solubility product, 
space space space space space space space straight K subscript ap space equals space open square brackets Ag to the power of plus close square brackets space open square brackets Cl to the power of minus close square brackets space equals space straight S space cross times space straight S or space space space space straight S squared space equals space straight K subscript sp or space space space straight S space equals space square root of straight S subscript sp end root space equals space square root of 1 space cross times space 10 to the power of negative 10 end exponent end root space space space space space space space space equals space 1 cross times space 10 to the power of negative 5 end exponent space mol space straight L to the power of negative 1 end exponent
Molecular mass of AgCl
                  = 108 + 35.5 = 143.5 
Hence solubility of AgCl
  = 143.5 x 1 x 10-5 g L-1
  = 14.35 x 10-4 g L-1

Some More Questions From Equilibrium Chapter

What is the role of forward and backward reactions at equilibrium of a reversible reaction?

What is a forward reaction?

What condition favours a reversible reaction?

What is a backward reaction?

What type of equilibrium is attained in a reversibe chemical change?

What is meant by a system at dynamic equilibrium?

discuss the effect of a catalyst on equilibrium ? 

At equilibrium, the mass of each of the reactants and products remains constant. Does it mean that the reaction has stopped? Explain.

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