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Equilibrium

Question
CBSEENCH11006607
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Calculate the solubility of A2X3 in pure water, assuming that neither kind of ion reacts with water. The solubility product of A2X3, Ksp = 1·1 × 10–23. 

Solution
straight A subscript 2 straight X subscript 3 space is space dissociated space as
              straight A subscript 2 straight X subscript 3 space rightwards arrow space space space space 2 straight A to the power of 3 plus end exponent space plus space 3 straight X to the power of 2 minus end exponent
Let space the space solubility space of space straight A subscript 2 straight X subscript 3 space be space straight S space mol space straight L to the power of negative 1 end exponent therefore space space open square brackets straight A to the power of 3 plus end exponent close square brackets space equals space 2 straight S semicolon space space space space open square brackets straight X to the power of 2 minus end exponent close square brackets space equals space 3 straight S Applying space the space law space of space solubility space product space space space space space space space space space space straight K subscript sp space equals space open square brackets straight A to the power of 3 plus end exponent close square brackets squared space open square brackets straight X to the power of 2 minus end exponent close square brackets cubed space space space space space space... left parenthesis 1 right parenthesis Putting space the space values space in space expression space left parenthesis 1 right parenthesis comma space we space have space 1.1 space cross times space 10 to the power of negative 23 end exponent space equals space left parenthesis 2 straight S right parenthesis squared space left parenthesis 3 straight S right parenthesis cubed space equals space 108 straight S to the power of 5 or space space space space space space space space space space space straight S to the power of 5 space equals space 1 space cross times space 10 to the power of negative 25 end exponent or space space space space space space space space space space space straight S space equals space left parenthesis 1.0 space cross times space 10 to the power of negative 25 end exponent right parenthesis to the power of 1 divided by 5 end exponent space space space space space space space space space space space space space space space space space space equals space 1.0 space cross times space 10 to the power of negative 5 end exponent space mol space straight L to the power of negative 1 end exponent space space space space space space space space space

Some More Questions From Equilibrium Chapter

Give an example from daily life in which there is gas solution equilibrium?

A crystal of common salt of a given mass is kept in its aqueous solution. After 24 hours, its mass remains the same. Is the crystal in equilibrium with the solution?

What is the role of forward and backward reactions at equilibrium of a reversible reaction?

What is a forward reaction?

What condition favours a reversible reaction?

What is a backward reaction?

What type of equilibrium is attained in a reversibe chemical change?

What is meant by a system at dynamic equilibrium?

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