What is the equivalent mass of the oxidation agent in the reaction

$SO subscript 2 plus space 2 straight H subscript 2 straight O space space rightwards arrow space space space 3 straight S space plus space 2 straight H subscript 2 straight O$

Solution

In this reaction, SO₂ oxidises H₂S, therefore, SO₂ acts as oxidising agent. During oxidation, four electrons are lost i.e.

SO subscript 2 space plus space 4 straight e to the power of minus space space space rightwards arrow space space space straight S space plus space 2 straight O to the power of 2 minus end exponent therefore space space Equivalent space man space of space SO subscript 2 space equals fraction numerator Molecular space mass space of space SO subscript 2 over denominator 4 end fraction space space space space space space space space space space space space space space space equals 64 over 4 space equals space 16

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