Question
Calculate the oxidation number of P in Ba(H2PO2)2.
Solution
Let x be the oxidation number of P.
Oxidation number of Ba =+2
Oxidation state of O2 =-2
Thus, oxidation number of P in Ba(H2PO2)2
+2 + 4(1) + 2x + 4(-2) = 0
or 2x - 2 = 0 or x = + 1
Oxidation number of Ba =+2
Oxidation state of O2 =-2
Thus, oxidation number of P in Ba(H2PO2)2
+2 + 4(1) + 2x + 4(-2) = 0
or 2x - 2 = 0 or x = + 1