How does the concept of solubility product help in finding out the solubility of sparingly soluble salts?

Solution

The concept of solubility product is helpful in finding out the solubility of the sparingly soluble salts in water if their K_sp values are known. For example, let AB be a sparingly soluble salt and suppose S mol L^–1 be the solubility of AB.

stack AB left parenthesis straight s right parenthesis with straight S space mol space straight L to the power of minus below space space space rightwards harpoon over leftwards harpoon with Water on top space space stack straight A to the power of plus left parenthesis aq right parenthesis with straight S space mol space straight L to the power of negative 1 end exponent below space plus space stack straight B to the power of minus left parenthesis aq right parenthesis with straight S space mol space straight L to the power of negative 1 end exponent below

Applying the law of solubility equilibrium,

straight K subscript sp space equals space open square brackets straight A to the power of plus close square brackets space open square brackets straight B to the power of minus close square brackets space space straight K subscript sp space equals space straight S space cross times space straight S

or space space space straight S squared space space equals space straight K subscript sp therefore space space straight S space equals space square root of straight K subscript sp end root

Knowing the solubility product K_sp (from tables), solubility can be calculated.

Some More Questions From Equilibrium Chapter

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Equilibrium

How does the concept of solubility product help in finding out the solubility of sparingly soluble salts?

Some More Questions From Equilibrium Chapter

What is the role of forward and backward reactions at equilibrium of a reversible reaction?

What is a forward reaction?

What condition favours a reversible reaction?

What is a backward reaction?

What type of equilibrium is attained in a reversibe chemical change?

What is meant by a system at dynamic equilibrium?

discuss the effect of a catalyst on equilibrium ?

At equilibrium, the mass of each of the reactants and products remains constant. Does it mean that the reaction has stopped? Explain.

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