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Equilibrium

Question
CBSEENCH11006594

Calculate the pH of:
(i) an acidic buffer mixture 
(ii) a basic buffer mixture.
Or
Derive Henderson’s equation for an acidic and basic buffer mixture.
Or
Derive the following equation for the pH of an acidic buffer:
pH space equals space pK subscript straight a space plus space log space fraction numerator open vertical bar Salt close vertical bar over denominator open vertical bar Acid close vertical bar end fraction

Solution
For acidic buffer mixture: Consider an acid buffer. Let it be a mixture of HA (weak acid) and its salt with a strong base, BA. A weak acid is only ionised to a small extent.
HA space rightwards harpoon over leftwards harpoon space space space straight H to the power of plus space plus space space straight A to the power of minus
Applying the law of chemical equilibrium, we get,
                     straight K subscript straight a space equals space fraction numerator open square brackets straight H to the power of plus close square brackets space open square brackets straight A to the power of minus close square brackets over denominator open square brackets HA close square brackets end fraction
where space straight K subscript straight a space is space the space dissociation space constant space of space the space acid. space
therefore space space space space space space space space open square brackets straight H to the power of plus close square brackets space equals space straight K subscript straight a space fraction numerator open square brackets HA close square brackets over denominator open square brackets straight A to the power of minus close square brackets end fraction space space space space space space space space space space... left parenthesis 1 right parenthesis
The space salt space BA space being space strong space electrolyte space dissociates space
almost space completely space in space the space solution.
space space space space BA space space rightwards arrow space space space straight B to the power of plus space plus space straight A to the power of minus
Due to the increase in the concentration of A ions the dissociation of the weak acid is further suppressed due to common ion effect. The concentration of weak acid molecules is taken as the concentration of HA and the concentration of the salt is the concentration of A ions. Thus,
[HA] = [Acid]
[BA] = [A-] = [Salt]
Substituting the values of [HA] and [A] in expression (1), we have.
open square brackets straight H to the power of plus close square brackets space equals space straight K subscript straight a space fraction numerator open square brackets Acid close square brackets over denominator open square brackets Salt close square brackets end fraction
Taking logarithm of both the sides, we get,
log space open square brackets straight H to the power of plus close square brackets space equals space log space straight K subscript straight a space plus space log space fraction numerator open square brackets Acid close square brackets over denominator open square brackets Salt close square brackets end fraction
or space space space minus log space open square brackets straight H to the power of plus close square brackets space equals space minus log space straight K subscript straight a space minus space log space fraction numerator open square brackets Acid close square brackets over denominator open square brackets Salt close square brackets end fraction
or space space space space space pH space equals space pK subscript straight a space plus space log space fraction numerator open square brackets Salt close square brackets over denominator open square brackets Acid close square brackets end fraction
This equation is known as Henderson equation. It helps in calculating the pH value of the buffer solution if the concentration of acid, as well as the salt, is known.
For basic buffer mixture: Proceeding exactly in a similar way as above, the expression for the pH of a basic buffer mixture (BOH + BA) can be obtained. BOH being a weak base dissociates to a small extent.
space space space space space space space space space space space BOH space space space rightwards harpoon over leftwards harpoon space space space straight B to the power of plus space plus space OH to the power of minus
or space space space space space space space space space space straight K subscript straight b space equals space fraction numerator open square brackets straight B to the power of plus close square brackets open square brackets OH to the power of minus close square brackets over denominator open square brackets BOH close square brackets end fraction
where space straight K subscript straight b space is space the space dissociation space constant space of space the space base comma space
or space space space space space open square brackets OH to the power of minus close square brackets space equals space straight K subscript straight b space cross times space fraction numerator open square brackets BOH close square brackets over denominator open square brackets straight B to the power of plus close square brackets end fraction space space space space space space space... left parenthesis 1 right parenthesis
The salt BA being strong electrolyte dissociates almost completely. 
                             space space space space space space BA space space rightwards arrow space space space straight B to the power of plus space plus space straight A to the power of minus
Now space space space space space open square brackets BOH close square brackets space equals space open square brackets Base close square brackets
space space space open square brackets BA close square brackets space equals open square brackets straight B to the power of plus close square brackets space equals space open square brackets Salt close square brackets
Substituting space the space values space of space open square brackets BOH close square brackets space and space open square brackets straight B to the power of plus close square brackets space
in space expression space left parenthesis 1 right parenthesis comma space we space have comma space
space space space open square brackets OH to the power of minus close square brackets space equals space straight K subscript straight b space cross times space fraction numerator open square brackets Base close square brackets over denominator open square brackets Salt close square brackets end fraction
Taking logarithm of both the sides we get,
     log space open square brackets OH to the power of minus close square brackets space equals space log space straight K subscript straight b space plus space log space fraction numerator open square brackets Base close square brackets over denominator open square brackets Salt close square brackets end fraction
minus log space open square brackets OH to the power of minus close square brackets space equals space minus log space straight K subscript straight b space minus space log space fraction numerator open square brackets Base close square brackets over denominator open square brackets Salt close square brackets end fraction
pOH space equals space pK subscript straight b space plus space log space fraction numerator open square brackets Salt close square brackets over denominator open square brackets Base close square brackets end fraction space space space space space space space space... left parenthesis 2 right parenthesis
This is also called Henderson equation. The pH of the basic buffer solution can be obtained by the following expression:
        pH space plus space pOH space equals space 14
or space space space space space space space space space space pH space space equals space 14 space minus space pOH
Substituting space the space values space of space pOH comma
space space pH space equals space 14 minus space pK subscript straight b space minus space log space fraction numerator open square brackets Salt close square brackets over denominator open square brackets Base close square brackets end fraction