Question
How will you explain buffer action of aqueous solution of ammonium acetate?
Solution
Ammonium acetate on dissolution dissociates completely as ions.

(i) If an acid (say HCl) is added to this solution, H3O+ ions generated by the acid combine with CH3COO– ion to form weakly ionised acetic acid molecules

Since most of H3O+ ions are consumed by CH3COO– ions to form slightly dissociated acetic acid, hence the pH value of the solution does not undergo any change.
Now suppose a base (say NaOH) is added to ammonium acetate solution. The OH– ions liberated by the base will be consumed by
ions to form very slightly dissociated NH4OH.

Since most of the OH– ions are consumed by the
ions, hence there is very little or no change in the pH value of ammonium acetate.
Thus, CH3COONH4 has reserve acidity due to
ions and reserve alkalinity due to CH3COO– ions.

(i) If an acid (say HCl) is added to this solution, H3O+ ions generated by the acid combine with CH3COO– ion to form weakly ionised acetic acid molecules

Since most of H3O+ ions are consumed by CH3COO– ions to form slightly dissociated acetic acid, hence the pH value of the solution does not undergo any change.
Now suppose a base (say NaOH) is added to ammonium acetate solution. The OH– ions liberated by the base will be consumed by


Since most of the OH– ions are consumed by the

Thus, CH3COONH4 has reserve acidity due to
