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Equilibrium

Question
CBSEENCH11006593

How will you explain buffer action of aqueous solution of ammonium acetate?

Solution
Ammonium acetate on dissolution dissociates completely as ions.
CH subscript 3 COONH subscript 4 left parenthesis aq right parenthesis space space rightwards arrow space space space CH subscript 3 COO to the power of minus left parenthesis aq right parenthesis space plus space NH subscript 4 superscript plus space left parenthesis aq right parenthesis
(i) If an acid (say HCl) is added to this solution, H3O+ ions generated by the acid combine with CH3COO ion to form weakly ionised acetic acid molecules
stack CH subscript 3 COO with left parenthesis Buffer right parenthesis below left parenthesis aq right parenthesis space plus space straight H subscript 3 straight O to the power of plus space space space space rightwards arrow space space space space space stack CH subscript 3 COOH with left parenthesis weakly space ionised right parenthesis below space plus space straight H subscript 2 straight O
Since most of H3O+ ions are consumed by CH3COO ions to form slightly dissociated acetic acid, hence the pH value of the solution does not undergo any change.
Now suppose a base (say NaOH) is added to ammonium acetate solution. The OH ions liberated by the base will be consumed by NH subscript 4 superscript plusions to form very slightly dissociated NH4OH. 

stack NH subscript 4 superscript plus left parenthesis aq right parenthesis with From space buffer below space plus space OH to the power of minus space left parenthesis aq right parenthesis space space rightwards arrow space space NH subscript 4 OH
Since most of the OH ions are consumed by the NH subscript 4 superscript plus ions, hence there is very little or no change in the pH value of ammonium acetate.
Thus, CH3COONH4 has reserve acidity due to NH subscript 4 superscript plus ions and reserve alkalinity due to CH3COO ions.