Calculate the degree of hydrolysis of 0.015 M solution of NH 4 Cl. Given K b for NH 4 OH is 1·8 × 10 –5 , K w = 10 –14 at 25°C. - Wired Faculty

Equilibrium

Question

Calculate the degree of hydrolysis of 0.015 M solution of NH₄Cl. Given K_b for NH₄OH is 1·8 × 10^–5, K_w = 10^–14at 25°C.

Solution

Since NH₄Cl is the salt of weak base with a strong acid.

therefore space space space space straight K subscript straight h space equals space straight K subscript straight w over straight K subscript straight b space equals fraction numerator 10 to the power of negative 14 end exponent over denominator 1.8 space cross times space 10 to the power of negative 5 end exponent end fraction space equals space 0.555 space cross times space 10 to the power of negative 9 end exponent space space space space space space space equals space square root of 370 space cross times space 10 to the power of negative 10 end exponent end root space equals space 19.23 space cross times space 10 to the power of negative 5 end exponent therefore space space space straight alpha space equals space 1.923 space cross times space 10 to the power of negative 4 end exponent

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