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Equilibrium

Question
CBSEENCH11006582

Derive space straight K subscript straight h space equals space fraction numerator straight K subscript straight w over denominator straight K subscript straight a space straight K subscript straight b end fraction
for space straight a space solution space of space salt space of space weak space acid space and space weak space base.

Solution
Suppose the salt of weak acid and weak base is BA and its hydrolysis is represented as:
         BA with salt below space plus space straight H subscript 2 straight O space space leftwards harpoon over rightwards harpoon space space space BOH with weak below space plus space HA with weak below
or space space straight B to the power of plus space plus space straight A to the power of minus space space plus space straight H subscript 2 straight O space space rightwards harpoon over leftwards harpoon space space space space BOH space plus space HA
It involves both cationic as well as ionic hydrolysis.
Now comma space space space straight K subscript straight h space equals space fraction numerator open square brackets BOH close square brackets open square brackets HA close square brackets over denominator open square brackets straight B to the power of plus close square brackets open square brackets straight A to the power of minus close square brackets end fraction space space space space space space space space... left parenthesis 1 right parenthesis
Also space for space weak space acid comma space
space space space space space space HA space rightwards harpoon over leftwards harpoon space space straight H to the power of plus space plus space straight A to the power of minus
space space space space space space straight K subscript straight a space equals space fraction numerator open square brackets straight H to the power of plus close square brackets open square brackets straight A to the power of minus close square brackets over denominator open square brackets HA close square brackets end fraction space space space space space space space space space space space space space space space... left parenthesis 2 right parenthesis
For space weak space base comma
space space space space space space BOH space leftwards harpoon over rightwards harpoon space space straight B to the power of plus space plus space OH to the power of minus
space space space space space straight K subscript straight b space space equals space fraction numerator open square brackets straight B to the power of plus close square brackets open square brackets OH to the power of minus close square brackets over denominator open square brackets BOH close square brackets end fraction space space space space space space space space space space space space space space... left parenthesis 3 right parenthesis

Also comma space space space space straight K subscript straight w space equals space open square brackets straight H to the power of plus close square brackets space open square brackets OH to the power of minus close square brackets space space space space space space space space space... left parenthesis 4 right parenthesis
Multiplying equations (1), (2) and (3),
straight K subscript straight h. space straight K subscript straight a space. space straight K subscript straight b space equals space open square brackets straight H to the power of plus close square brackets space open square brackets OH to the power of plus close square brackets space equals space straight K subscript straight w space space space space left square bracket From space eq. space left parenthesis 4 right parenthesis right square bracket
space space therefore space space space space space space straight K subscript straight h space equals space fraction numerator straight K subscript straight w over denominator straight K subscript straight a space straight K subscript straight b end fraction