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Equilibrium

Question
CBSEENCH11006569
Wired Faculty App

The pH of 0.1 M monobasic acid is 4.50. Calculate the concentration of species H+, A– and HA at equilibrium. Also, determine the values of Ka and pKa of the monobasic acid. A and HA at equilibrium. Also, determine the values of Ka and pKa of the monobasic acid.

Solution
We space know comma space space space space minus log space open square brackets straight H to the power of plus close square brackets space equals space pH space equals space 4.50 or space space log space open square brackets straight H to the power of plus close square brackets space equals space minus 4.50 space equals space minus 4 minus 0.50 space plus space 1 space minus space 1 space space space space space space space space space space space space space space space space space space equals 5 with bar on top.50 therefore space space space space space space space space open square brackets straight H to the power of plus close square brackets space equals space antilog space left parenthesis 5 with bar on top space.50 right parenthesis space equals space 3.16 space cross times space 10 to the power of negative 5 end exponent straight M therefore space space space space space space space space space open square brackets straight H to the power of plus close square brackets space equals space open square brackets straight A to the power of minus close square brackets space equals space 3.16 space cross times space 10 to the power of negative 5 end exponent straight M space space space space space space space space space space space space space space space space space space space open vertical bar HA close vertical bar space equals space left parenthesis 0.1 space minus space 3.16 space cross times 10 to the power of negative 5 end exponent right parenthesis space equals space 0.1 space straight M

  straight K subscript straight a space equals space fraction numerator open square brackets straight H to the power of plus close square brackets space open square brackets straight A to the power of minus close square brackets over denominator open square brackets HA close square brackets end fraction space equals space fraction numerator left parenthesis 3.16 space cross times space 10 to the power of negative 5 end exponent right parenthesis squared over denominator 0.1 end fraction space space space space equals space 1.0 space cross times space 10 to the power of negative 8 end exponent pK subscript straight a space equals space minus log space straight K subscript straight a space equals space minus log space left square bracket 10 to the power of negative 8 end exponent right square bracket space equals space 8
 

Some More Questions From Equilibrium Chapter

What is the role of forward and backward reactions at equilibrium of a reversible reaction?

What is a forward reaction?

What condition favours a reversible reaction?

What is a backward reaction?

What type of equilibrium is attained in a reversibe chemical change?

What is meant by a system at dynamic equilibrium?

discuss the effect of a catalyst on equilibrium ? 

At equilibrium, the mass of each of the reactants and products remains constant. Does it mean that the reaction has stopped? Explain.

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