+91-8076753736[email protected]
logo
logo
-->

Equilibrium

Question
CBSEENCH11006558
Wired Faculty App

The ionisation constant of acetic acid is 1·74 × 10–5. Calculate the degree of dissociation of acetic acid in its 0·05 M solution. Calculate the concentration of acetate ion in the solution and its pH. 

Solution
The dissociation of acetic acid may be represented as
CH subscript 3 COOH space space rightwards harpoon over leftwards harpoon space space space CH subscript 3 COO to the power of minus space plus space straight H to the power of plus space space space straight K subscript straight a space equals space fraction numerator open square brackets CH subscript 3 COO to the power of minus close square brackets space open square brackets straight H to the power of plus close square brackets over denominator open square brackets CH subscript 3 COOH close square brackets end fraction space equals space fraction numerator open square brackets straight H to the power of plus close square brackets squared over denominator open square brackets CH subscript 3 COOH close square brackets end fraction or space space open square brackets straight H to the power of plus close square brackets space equals space square root of straight K subscript straight a open square brackets CH subscript 3 COOH close square brackets end root space space space space space space space space space space space equals square root of left parenthesis 1.74 space cross times space 10 to the power of negative 5 end exponent right parenthesis thin space left parenthesis 5 space cross times space 10 to the power of negative 2 end exponent right parenthesis end root space space space space space space space space space space space equals space 9.33 space cross times space 10 to the power of negative 4 end exponent straight M open square brackets CH subscript 3 COO to the power of minus close square brackets space equals space open square brackets straight H to the power of plus close square brackets space equals space 9.33 space cross times space 10 to the power of negative 4 end exponent straight M space space space space pH space equals space space minus log space left parenthesis 9.33 space cross times space 10 to the power of negative 4 end exponent right parenthesis space equals space 4 space minus space 0.9699 space space space space space space space space space equals space 4 minus 0.97 space equals 3.03

Some More Questions From Equilibrium Chapter

A crystal of common salt of a given mass is kept in its aqueous solution. After 24 hours, its mass remains the same. Is the crystal in equilibrium with the solution?

What is the role of forward and backward reactions at equilibrium of a reversible reaction?

What is a forward reaction?

What condition favours a reversible reaction?

What is a backward reaction?

What type of equilibrium is attained in a reversibe chemical change?

What is meant by a system at dynamic equilibrium?

discuss the effect of a catalyst on equilibrium ? 

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation