Question
Arrange the following in decreasing order of acidic strength:
(i) HOCl (Ka = 3·0 × 10–8)
(ii) HCN (Ka = 4·0 × 10–10)
(iii) HNO3 (Ka = 4·5 × 10–4)
(iv) HF (Ka = 6·7 × 10–4)
Solution
Greater the Ka value, stronger will be the acid.
∴
Decreasing order of acidic strength is
HF > HNO3 > HOCl > HCN.
