Question
Calculate the pH of a solution obtained by mixing 150 mL of 0.1 N - NaOH and 150 ml of 0.2 N - HCl.
Solution
In such problems of acid and base mixture solution, we should determine the volume of each having unit normality (or molarity).
Now 150 ml of
are neutralised by 15 mL of N-HCl
HCl left unused after mixing the two solutions
= (30 - 15) i.e. 15 mL of N-solution
Total , volume of the solution after mixing
= 150 + 150 = 300 mL
Since HCl is a strong electrolyte, it is completely dissociated.
Now 150 ml of
are neutralised by 15 mL of N-HClHCl left unused after mixing the two solutions
= (30 - 15) i.e. 15 mL of N-solution
Total , volume of the solution after mixing
= 150 + 150 = 300 mL
Since HCl is a strong electrolyte, it is completely dissociated.
