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Equilibrium

Question
CBSEENCH11006544
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Calculate the pH of a 1·0 × 10–8 M solution of HCl.

Solution
The [H3O+] is obtained from the following two ionisation reactions:
left parenthesis straight i right parenthesis space HCl space left parenthesis aq right parenthesis space plus space straight H subscript 2 straight O left parenthesis l right parenthesis space space rightwards harpoon over leftwards harpoon space space space straight H subscript 3 straight O to the power of plus left parenthesis aq right parenthesis space plus space OH to the power of minus left parenthesis aq right parenthesis left parenthesis ii right parenthesis space 2 straight H subscript 2 straight O space rightwards harpoon over leftwards harpoon space space space space straight H subscript 3 straight O to the power of plus space left parenthesis aq right parenthesis space plus space OH to the power of minus left parenthesis aq right parenthesis space space space therefore space space space From space acid semicolon space space space open square brackets straight H subscript 3 straight O to the power of plus close square brackets space equals space 10 to the power of negative 8 end exponent straight M From space water semicolon space space open square brackets straight H subscript 3 straight O to the power of plus close square brackets space equals space open square brackets OH to the power of minus close square brackets space equals space straight x space mol space straight L to the power of negative 1 end exponent left parenthesis aq right parenthesis

Thus space in space solution comma space we space have space space space space open square brackets straight H subscript 3 straight O to the power of plus close square brackets space equals space left parenthesis 10 to the power of negative 8 end exponent space plus space straight x right parenthesis space straight M space and space open square brackets OH to the power of minus close square brackets space equals space straight x space straight M
We know,
 open square brackets straight H subscript 3 straight O to the power of plus close square brackets space open square brackets OH to the power of minus close square brackets space equals straight K subscript straight w space equals space 10 to the power of negative 14 end exponent
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straight i. straight e. space open square brackets OH to the power of minus close square brackets space equals space 9.5125 space cross times space 10 to the power of negative 8 end exponent straight M or space space space space space space straight p subscript OH space equals space minus log space open square brackets OH to the power of minus close square brackets space space space space space space space space space space space space space space space equals space minus log left parenthesis 9.5125 space cross times space 10 to the power of negative 8 end exponent right parenthesis space space space space space space space space space space space space space space space equals space 8 minus 0.9783 space equals space 7.02 pH space equals space 14 minus space straight p subscript OH space equals 14 minus 7.02 space equals 6.98

Some More Questions From Equilibrium Chapter

Which measurable property becomes constant in water vapour equilibrium?

Give an example from daily life in which there is gas solution equilibrium?

A crystal of common salt of a given mass is kept in its aqueous solution. After 24 hours, its mass remains the same. Is the crystal in equilibrium with the solution?

What is the role of forward and backward reactions at equilibrium of a reversible reaction?

What is a forward reaction?

What condition favours a reversible reaction?

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