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Equilibrium

Question
CBSEENCH11006436

The value of increment straight G degree for the phoshorylation of glucose in glycolysis is 13.8 kJ/mol. Find the value of Kc at 298 K.

Solution
space increment straight G degree space equals space minus RT space ln space straight K subscript straight c space equals space minus 2.303 space RT space log space straight K subscript straight c               ...(1)
 Here comma space increment straight G degree space equals 13.8 space kJ space mol to the power of negative 1 end exponent space equals space 13.8 space cross times space 10 cubed straight J space mol to the power of negative 1 end exponent
space space space space space space space space space space straight R space equals space 8.314 space JK to the power of negative 1 end exponent mol to the power of negative 1 end exponent
space space space space space space space space space space straight T space equals space 298 space straight K space

   Putting the values in expression (1), we have

13.8 space cross times space 10 cubed straight J space mol to the power of negative 1 end exponent space equals space 2.303 space cross times space left parenthesis 8.314 space JK to the power of negative 1 end exponent space mol to the power of negative 1 end exponent right parenthesis space cross times space left parenthesis 298 straight K right parenthesis space log space straight K subscript straight c
 On solving,
straight K subscript straight c space equals space 3.81 space cross times space 10 to the power of negative 3 end exponent