Question
At 700K, equilibrium constant for the reaction:
is 54.8. If 0.5 mole/litre of HI(g) is present at equilibrium at 700K, what are the concentration of H2(g) and I2(g) assuming that we initially started with HI(g) and allowed it to reach equilibrium at 700 K?
Solution
Here, equilibrium constant for the reaction,
is 54.8 . Thus the equilibrium constant for the reverse reaction
Concentration of HI at equilibrium = 0.5 mole/litre[given]
The concentration of H2 and I2 at equilibrium will be same.
Suppose each of them = x mole /litre
Applying law of chemical equilibrium to the above reaction,
Substituting the values, we have,
is 54.8 . Thus the equilibrium constant for the reverse reaction
Concentration of HI at equilibrium = 0.5 mole/litre[given]
The concentration of H2 and I2 at equilibrium will be same.
Suppose each of them = x mole /litre
Applying law of chemical equilibrium to the above reaction,
Substituting the values, we have,
