At 450K, K p = 2·0 × 10 10 /bar for the given reaction at equilibrium: What is K c at this temperature? - Wired Faculty

Question

At 450K, K_p = 2·0 × 10¹⁰/bar for the given reaction at equilibrium:
$2 SO subscript 2 left parenthesis straight g right parenthesis space plus space straight O subscript 2 left parenthesis straight g right parenthesis space space space rightwards harpoon over leftwards harpoon space space 2 SO subscript 3 left parenthesis straight g right parenthesis$

What is K_c at this temperature?

Solution

The reversible reaction is

2 SO subscript 2 left parenthesis straight g right parenthesis space plus space straight O subscript 2 left parenthesis straight g right parenthesis space rightwards harpoon over leftwards harpoon space space 2 SO subscript 3 left parenthesis straight g right parenthesis

We know,

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...(1)

space Here comma space space increment straight n space equals space 2 minus 3 space equals space minus 1 space space space space space space space space space space space space space straight T space equals space 450 space straight K space space space space space space space space space space straight K subscript straight p space equals space 2.0 space cross times space 10 to the power of 10 space bar to the power of negative 1 end exponent

Putting the values in expression (1), we have

2.0 space cross times space 10 to the power of negative 10 end exponent bar to the power of negative 1 end exponent space equals space straight K subscript straight c left parenthesis RT right parenthesis to the power of increment straight n end exponent

therefore space space space straight K subscript straight c space equals space 2.0 space cross times space 10 to the power of negative 10 end exponent bar to the power of negative 1 end exponent space left parenthesis RT right parenthesis to the power of negative increment straight n end exponent space space space space space space space space space space space equals space 2.0 space cross times space 10 to the power of negative 10 end exponent space bar to the power of negative 1 end exponent left parenthesis RT right parenthesis space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space open square brackets because space increment straight n space equals space minus 1 close square brackets space space space space space space space space space space space space space space space space space space space space space space space space space space

equals space 2.0 space cross times space 10 to the power of negative 10 end exponent bar to the power of negative 1 end exponent left parenthesis 0.0831 space straight L space bar space straight K to the power of negative 1 end exponent space mol to the power of negative 1 end exponent right parenthesis space left parenthesis 450 space straight K right parenthesis equals space 7.48 space cross times space 10 to the power of 11 straight L space mol to the power of negative 1 end exponent

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Equilibrium

Some More Questions From Equilibrium Chapter

A crystal of common salt of a given mass is kept in its aqueous solution. After 24 hours, its mass remains the same. Is the crystal in equilibrium with the solution?

What is the role of forward and backward reactions at equilibrium of a reversible reaction?

What is a forward reaction?

What condition favours a reversible reaction?

What is a backward reaction?

What type of equilibrium is attained in a reversibe chemical change?

What is meant by a system at dynamic equilibrium?

discuss the effect of a catalyst on equilibrium ?

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