For the equilibrium the value of the equilibrium constant K C is Calculate K p for the reaction at this temperature. - Wired Faculty

Equilibrium

Question

For the equilibrium $2 NOCl left parenthesis straight g right parenthesis space rightwards harpoon over leftwards harpoon space space space 2 NO left parenthesis straight g right parenthesis space plus space Cl subscript 2 left parenthesis straight g right parenthesis$ the value of the equilibrium constant K_C is $3.75 space cross times space 10 to the power of negative 6 end exponent space space at space 1069 space straight K.$ Calculate K_pfor the reaction at this temperature.

Solution

The reversible reaction is

2 NOCl left parenthesis straight g right parenthesis space space rightwards harpoon over leftwards harpoon space space space 2 NO left parenthesis straight g right parenthesis space plus space Cl subscript 2 left parenthesis straight g right parenthesis

We know,

straight K subscript straight p space equals space straight K subscript straight c left parenthesis RT right parenthesis to the power of increment straight n end exponent

...(1)
Here,

straight K subscript straight C space equals space 3.75 space cross times space 10 to the power of negative 6 end exponent semicolon

straight R space equals space 0.0831 thin space straight L space bar space straight K to the power of negative 1 end exponent space mol to the power of negative 1 end exponent straight T space equals space 1069 space straight K semicolon space increment straight n space equals space left parenthesis 2 plus 1 right parenthesis minus 2 space equals space 1

Substituting the value in eq. (1), we have,

straight K subscript straight p space equals space 3.75 space cross times space 10 to the power of negative 6 end exponent left parenthesis 0.0831 space cross times space 1069 right parenthesis space space space space space equals space 3.33 space cross times space 10 to the power of negative 2 end exponent

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