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Equilibrium

Question
CBSEENCH11006409

At 473K, equilibrium constant Kfor decomposition of phosphorus pentachloride, PCl5 is 8·3 × 10–3. If decomposition is depicted as

PCl subscript 5 left parenthesis straight g right parenthesis space space rightwards harpoon over leftwards harpoon space space PCl subscript 3 left parenthesis straight g right parenthesis space plus space Cl subscript 2 left parenthesis straight g right parenthesis comma space space increment subscript straight r straight H to the power of 0 space equals space 124.0 space kJ space mol to the power of negative 1 end exponent

(a) write an expression for Kc for the reaction.

(b) what is the value of Kc for the reverse reaction at the same temperature?

(c) what would be the effect on K
c if:
(i) more PCl5 is added
(ii) pressure is increased
(iii) temperature is increased? 

Solution
left parenthesis straight a right parenthesis space straight K subscript straight c space equals space fraction numerator open square brackets PCl subscript 3 close square brackets space open square brackets Cl subscript 2 close square brackets over denominator open square brackets PCl subscript 5 close square brackets end fraction space equals space 8.3 space cross times 10 to the power of negative 3 end exponent
(b) Kc for reverse reaction
    equals space fraction numerator 1 over denominator straight K subscript straight c space for space forward space observation end fraction
equals space fraction numerator 1 over denominator 8.3 space cross times space 10 to the power of negative 3 end exponent end fraction space equals space 120.48

(c)
(i) Kc remains unchanged when more PClis added.
(ii) When pressure is increased, Kc remains unchanged.
(iii) As given reaction is endothermic, on increasing the temperature, Af will increase.
As straight K subscript straight c space equals space straight k subscript straight f over straight k subscript straight b comma space straight K subscript straight c  will increase with the increase of temperature.