Question
Write correctly the balanced net ionic equation for the reaction whose equilibrium constant at 298K is:
(i) Kb(CH3NH2) = 4·4 × 10–5
(ii) KaS) = 1·0 × 10–7
(iii) Ka (HCN) = 4·0 × 10–10
(iv) Kb(NH3) = 1·8 × 10–5
Solution
