Question
Write the correct balanced net ionic equation for the reaction whose equilibrium constant at 298K is:
(i) Ka(C6H5COOH) = 6·3 × 10–5
(ii) Ka(H2C2O4) = 5·4 × 10–2
(iii) Ka ( HSO3–) = 2·8 × 10–7
(iv) Kb(OCl–) = 9·1 × 10–7
Solution
