Question
The following concentrations were obtained for the formation of NH3 from N2and H2 at equilibrium at 500K. [N2] = 1·5 × 10–2 M, [H2] = 3·0 × 10–2M and [NH3] = 1·2 × 10–2 M. Calculate the equilibrium constant.
Solution
The reaction is
We have given,
[N2] = 1·5 × 10–2 M
[H2] = 3·0 × 10–2M
[NH3] = 1·2 × 10–2 M
Applying the law of chemical equilibrium, we have
Putting the values in expression (1), we have
We have given,
[N2] = 1·5 × 10–2 M
[H2] = 3·0 × 10–2M
[NH3] = 1·2 × 10–2 M
Applying the law of chemical equilibrium, we have
Putting the values in expression (1), we have
