Question
At equilibrium, the concentration of N2 = 3·0 × 10–3 M, O2 = 4·2 × 10–3 M and NO = 2·8 × 10–3 M in a sealed vessel at 800K. What will be Kc for the reaction:
Solution
We have given,
N2 = 3·0 × 10–3 M,
O2 = 4·2 × 10–3 M
NO = 2·8 × 10–3 M
Applying the law of chemical equilibrium. We have
Putting the values in expression (1), we have
