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Equilibrium

Question
CBSEENCH11006327

A quantity of PCl5 was heated in a 10 litre vessel at 250°C. 
PCl subscript 5 left parenthesis straight g right parenthesis space rightwards harpoon over leftwards harpoon space PCl subscript 3 left parenthesis straight g right parenthesis plus space Cl subscript 2 left parenthesis straight g right parenthesis. At equilibrium the vessel contains 0.1 mole of PCl subscript 5 comma 0.20 mole of PCl subscript 3 and 0.20 mole of Cl2. What is the value of equilibrium constant of the reaction?

Solution
straight K space equals space fraction numerator open vertical bar PCl subscript 3 close vertical bar space space open vertical bar Cl subscript 2 close vertical bar over denominator open vertical bar PCl subscript 5 close vertical bar end fraction
space space space equals space fraction numerator open parentheses begin display style fraction numerator 0.20 over denominator 10 end fraction end style close parentheses space open parentheses begin display style fraction numerator 0.20 over denominator 10 end fraction end style close parentheses over denominator open parentheses begin display style fraction numerator 0.1 over denominator 10 end fraction end style close parentheses end fraction
space space space equals fraction numerator 0.02 space cross times space 0.02 over denominator space 0.01 end fraction space equals space 0.04