The value of K c for the reaction is at If the equilibrium concentration of in air at is what is the concentration of O 3 ?v - Wired Faculty

Question

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The value of K_c for the reaction $3 straight O subscript 2 left parenthesis straight g right parenthesis space space space rightwards harpoon over leftwards harpoon space space space space 2 straight O subscript 3 left parenthesis straight g right parenthesis$ is $2.0 space cross times space 10 to the power of negative 50 end exponent$ at $25 degree straight C.$ If the equilibrium concentration of $straight O subscript 2$ in air at $25 degree straight C$ is $1.6 space cross times space 10 to the power of negative 2 end exponent comma$ what is the concentration of O₃?v

Solution

The given reversible reaction is
$3 straight O subscript 2 left parenthesis straight g right parenthesis space rightwards harpoon over leftwards harpoon space space space 2 straight O subscript 3 left parenthesis straight g right parenthesis$
Applying the law of chemical equilibrium
$straight K subscript straight c space equals space open square brackets straight O subscript 3 left parenthesis straight g right parenthesis close square brackets squared over open square brackets straight O subscript 2 left parenthesis straight g right parenthesis close square brackets cubed$ ...(1)
Putting this value in expression (1), we have

$2.0 space cross times space 10 to the power of negative 50 end exponent space equals space fraction numerator open square brackets straight O subscript 3 left parenthesis straight g right parenthesis close square brackets squared over denominator left parenthesis 1.6 space cross times space 10 to the power of negative 2 end exponent right parenthesis cubed end fraction or space space space space open square brackets straight O subscript 3 left parenthesis straight g right parenthesis close square brackets squared space equals space left parenthesis 2.0 space cross times space 10 to the power of negative 50 end exponent right parenthesis space left parenthesis 1.6 space cross times space 10 to the power of negative 2 end exponent right parenthesis cubed space space space space space space space space space space space space space space space space space space space equals space 8.192 space cross times space 10 to the power of negative 56 end exponent or space space space open square brackets straight O subscript 3 left parenthesis straight g right parenthesis close square brackets space equals space 2.86 space cross times space 10 to the power of negative 28 end exponent straight M$

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Equilibrium

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