The value of for the reaction At a given time the composition of reaction mixture is In which direction the reaction will proceed? - Wired Faculty

Equilibrium

Question

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The value of $straight K subscript straight c$ for the reaction $2 straight A rightwards harpoon over leftwards harpoon space straight B plus straight C space is space 2 cross times space 10 to the power of negative 3 end exponent.$ At a given time the composition of reaction mixture is $open vertical bar straight A close vertical bar space equals open vertical bar straight B close vertical bar space equals space open vertical bar straight C close vertical bar space equals space 3 space cross times space 10 to the power of negative 4 end exponent straight M.$ In which direction the reaction will proceed?

Solution

For the above reaction
$straight Q subscript straight c space equals space fraction numerator open square brackets straight B close square brackets space open square brackets straight C close square brackets over denominator open square brackets straight A close square brackets squared end fraction$ ...(1)
Here,
$open square brackets straight A close square brackets space equals space open square brackets straight B close square brackets space equals space open square brackets straight C close square brackets space equals space 3 cross times 10 to the power of negative 4 end exponent straight M comma$
Putting the values in expression (1), we have
$straight Q subscript straight C space equals space fraction numerator left parenthesis 3 cross times 10 to the power of negative 4 end exponent straight M right parenthesis left parenthesis 3 cross times 10 to the power of negative 4 end exponent straight M right parenthesis over denominator left parenthesis 3 cross times 10 to the power of negative 4 end exponent straight M right parenthesis squared end fraction space equals 1$
As Q_c > K_c, so the reaction will proceed in the reverse direction.