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Equilibrium

Question
CBSEENCH11006378

For the following equilibrium, Kc = 6·3 × 1014 at 1000 K
space NO left parenthesis straight g right parenthesis space plus space straight O subscript 3 left parenthesis straight g right parenthesis space rightwards harpoon over leftwards harpoon space space NO subscript 2 left parenthesis straight g right parenthesis plus straight O subscript 2 left parenthesis straight g right parenthesis

both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is Kc for the reverse reaction?

Solution

For the equilibrium.
space NO left parenthesis straight g right parenthesis plus space straight O subscript 3 left parenthesis straight g right parenthesis rightwards harpoon over leftwards harpoon space NO subscript 2 left parenthesis straight g right parenthesis space plus space straight O subscript 2 left parenthesis straight g right parenthesis
space space space space space straight K subscript straight C space equals space 6.3 space cross times space 10 to the power of 14
space therefore space space For space the space reverse space reaction
space straight K subscript straight c space equals space 1 over straight K subscript straight c space equals space fraction numerator 1 over denominator 6.3 space cross times space 10 to the power of 14 end fraction space equals space 1.59 space cross times space 10 to the power of negative 15 end exponent