Write the expression for the equilibrium constant K_c for each of the following reactions:
$Fe to the power of 3 plus end exponent left parenthesis aq right parenthesis space plus space 3 OH to the power of minus left parenthesis aq right parenthesis space space space leftwards harpoon over rightwards harpoon space Fe left parenthesis OH right parenthesis subscript 3 left parenthesis straight s right parenthesis$

Solution

space straight K subscript straight c space equals space fraction numerator open square brackets Fe left parenthesis OH right parenthesis subscript 3 left parenthesis straight s right parenthesis close square brackets over denominator open square brackets Fe to the power of 3 plus end exponent left parenthesis aq right parenthesis close square brackets space open square brackets OH to the power of minus left parenthesis aq right parenthesis close square brackets cubed end fraction space space space space space equals space fraction numerator 1 over denominator open square brackets Fe to the power of 3 plus end exponent left parenthesis aq right parenthesis close square brackets space open square brackets OH to the power of minus left parenthesis aq right parenthesis close square brackets cubed end fraction

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