-->

Thermodynamics

Question
CBSEENCH11006219

Calculate increment subscript straight r straight H to the power of 0 of tge reaction


The average bond enthalpies of C – H bond and C – Cl bond are 415 kJ mol
–1 and 326 kJ mol–1 respectively.

Solution

We know that,
space space increment subscript straight r straight H to the power of 0 space equals space sum from blank to blank of Bond space enthalpies subscript left parenthesis Reactants right parenthesis end subscript space
space space space space space space space space space space space space space space space space space space space space space space space space space minus space sum from blank to blank of Bond space enthalpy subscript left parenthesis Products right parenthesis end subscript

increment subscript straight r straight H to the power of 0 space equals space open square brackets 2 space cross times space straight H subscript straight C minus straight H end subscript superscript 0 space plus space 2 cross times straight H subscript straight C space minus space straight H end subscript superscript 0 close square brackets space minus space 0
space space space space space space space space space equals space 2 space cross times space 415 space plus space 2 space cross times space 326
space space space space space space space space space equals space 830 plus 652
space space space space space space space space space equals space 1482 space kJ