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Thermodynamics

Question
CBSEENCH11006200

When 1 gm of liquid naphthalene (C10H8) solidifies, 49 joules of heat is evolved. Calculate the enthalpy of fusion of naphthalene.

Solution
Gram molecular mass of naphthalene (C10H8) = 10 x 12 + 8 x 1 = 128 g
Heat evolved in the solidification of 1 g of naphthalene = 149 J
Heat evolved in the solidification of 128g of naphthalene =149 x 128 
                                                                                         = 19072 J
                                                                                         = 19.072 kJ
 therefore space space Enthalpy space of space solidification space left parenthesis increment straight H right parenthesis space equals space minus 19.072 space kJ
therefore space space space Enthalpy space of space fusion space open parentheses increment subscript fus straight H to the power of 0 close parentheses space equals space plus 19.072 space kJ