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Thermodynamics

Question
CBSEENCH11006293

(a) What are Exergonic and Endergonic reactions?

(b) Given that the standard heat of formation of NH3(g) as represented by the equation

1 half straight N subscript 2 left parenthesis straight g right parenthesis space plus space 3 over 2 straight H subscript 2 left parenthesis straight g right parenthesis space space rightwards arrow space space NH subscript 3 left parenthesis straight g right parenthesis

is – 46.191 kJ. The standard entropies of N2(g), H2(g) and NH3(g) are 191.62, 130.12 and 193.3 JK–1 mol–1 respectively. Calculate the standard free energy of formation (∆G0) for NH3. Is the reaction feasible?

Solution
(a) A reaction which is accompanied by the decrease of free energy is called exergonic reaction. All spontaneous processes are exergonic. It means in an exoergic reaction, ∆G is less than zero i.e. ∆G is negative.
A reaction Which is accompanied by the increase of free energy is called endergonic reaction. All non-spontaneous processes are endergonic. It means an endergonic reaction ∆G is greater than zero i.e. ∆G is positive.
(b) Here,
increment straight G to the power of 0 space equals negative 46.191 space kJ space equals space minus 46191 space straight J
space space straight T space equals space 298 space straight K
We know,
   increment straight S to the power of 0 space equals space straight S to the power of 0 subscript Products space minus space straight S to the power of 0 subscript Reactants
space space space space space space space equals straight S subscript NH subscript 3 end subscript superscript 0 space minus space open square brackets 1 half straight S subscript straight N subscript 2 end subscript superscript 0 space plus space 3 over 2 straight S subscript straight H subscript 2 end subscript superscript 0 close square brackets
space space space space space space space equals space 193.3 space minus space open square brackets 1 half cross times 191.72 plus 3 over 2 cross times 130.12 close square brackets
space space space space space space space equals 193.3 minus left square bracket 95.81 plus 3 cross times 65.06 right square bracket
space space space space space space space equals 193.3 space minus space left square bracket 95.18 plus 195.18 right square bracket
space space space space space space space equals negative 97.69 space straight J
Also,
increment subscript straight r straight G to the power of 0 space equals space increment subscript straight r straight H to the power of 0 space minus space straight T increment subscript straight r straight S to the power of 0
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space open square brackets Gibb apostrophe straight s space minus space Helmholtz space equation close square brackets
Substituting the values, we have,
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Since the value of ∆rG° is negative, the reaction is feasible.