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Thermodynamics

Question
CBSEENCH11006284

At 60°C, dinitrogen tetroxide is fifty percent dissociated. Calculate the standard free energy change at this temperature and at one atmosphere. 

Solution

N2O4 (g)     rightwards harpoon over leftwards harpoon       2NO2(g)
Initial 1 mole                 0
At eqn. 1 - 0.5           2 x 0.5
       = 0.5 mol            = 1 mol
Total number of moles = 0.5 + 1  = 1.5 mol
straight p subscript straight N subscript 2 straight O subscript 4 end subscript space equals fraction numerator 0.5 over denominator 1.5 space end fraction cross times 1 space space atm space equals space 1 third atm
straight p subscript NO subscript 2 end subscript space equals space fraction numerator 1 over denominator 1.5 end fraction cross times 1 space atm space equals space 2 over 3 atm

According to law of chemical equilibrium
 straight K subscript straight p space equals space straight p subscript NO subscript 2 end subscript over straight p subscript straight N subscript 2 straight O subscript 4 end subscript space equals space fraction numerator open parentheses begin display style 2 over 3 end style close parentheses squared over denominator open parentheses begin display style 1 third end style close parentheses end fraction space equals space 1.33 space atm


We know, 
       
 increment straight G to the power of 0 space equals space minus 2.303 space RT space log space straight K subscript straight p space space space space space space... left parenthesis 1 right parenthesis
Substituting the values in equation (1), we get
            increment straight G to the power of 0 space equals space minus 2.303 space left parenthesis 8.314 space JK to the power of negative 1 end exponent space mol to the power of negative 1 end exponent right parenthesis thin space left parenthesis 333 space straight K right parenthesis space log space 1.33
space space space space space space space space equals space minus 790 space straight J space mol to the power of negative 1 end exponent