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Thermodynamics

Question
CBSEENCH11006278
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For the equilibrium
PCl subscript 5 space space rightwards harpoon over leftwards harpoon space space space space PCl subscript 3 left parenthesis straight g right parenthesis space plus space Cl subscript 2 left parenthesis straight g right parenthesis space at space 298 space straight K comma straight K space equals space 1.8 space cross times space 10 to the power of negative 7 end exponent, 
What is the ∆G0 for the reaction?

Solution

Here,   straight K space equals space 1.8 space cross times space 10 to the power of negative 7 end exponent comma space space space straight T space equals space 298 space straight K comma
We know, space increment subscript straight r straight G to the power of 0 space equals space minus 2.303 space RT space log space straight K
Substituting the values, we get,
  increment straight G to the power of 0 space equals space minus 2.303 space cross times space 8.314 space cross times space 298 space cross times space log space left parenthesis 1.8 space cross times space 10 to the power of negative 7 end exponent right parenthesis space equals space 34484.2 space straight J space equals 34.4842 space kJ space mol to the power of negative 1 end exponent

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