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Thermodynamics

Question
CBSEENCH11006266
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The following data is known about ZnSO4:
increment straight H space equals space 7.25 space kJ space mol to the power of negative 1 end exponent space and space increment straight S space equals space 7.0 space JK to the power of negative 1 end exponent space mol to the power of negative 1 end exponent Calculate its melting point.

Solution

At melting point, increment straight G space equals space 0 semicolon
                   increment straight H space equals space 7.25 space kJ space mol to the power of negative 1 end exponent semicolon increment straight S space equals space 7.0 space JK to the power of negative 1 end exponent space mol to the power of negative 1 end exponent space space space space space space space equals space 7.0 space cross times space 10 to the power of negative 3 end exponent kJ space straight K to the power of negative 1 end exponent space mol to the power of negative 1 end exponent
   Now comma space space space increment straight H space equals space straight T increment straight S therefore space space space space space space space straight T space equals space fraction numerator increment straight H over denominator increment straight S end fraction space equals space fraction numerator 7.25 space kJ space mol to the power of negative 1 end exponent over denominator 7 cross times 10 to the power of negative 3 end exponent space kJK to the power of negative 1 end exponent space mol to the power of negative 1 end exponent end fraction space space space space space space space space space space space equals 1035.7 space straight K

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