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Thermodynamics

Question
CBSEENCH11006251

What do you understand by:
(i) The entropy of fusion?
(ii) The entropy of vapourisation ?

Solution

(i) The entropy of fusion. It may be defined as the entropy change when one mole of the solid substance changes into liquid form at its melting point. For example when ice melts as
      Water space rightwards harpoon over leftwards harpoon space space Water space left parenthesis straight l right parenthesis comma space space then
increment straight S subscript fusion space equals space straight S subscript water space minus space straight S subscript ice space equals space fraction numerator increment straight H subscript fusion over denominator straight T subscript straight f end fraction
where ∆Hfusion is the enthalpy of fusion and Tis the fusion temperature. Since ∆Hfus is +ve, therefore ∆Sjfus is +ve, hence the process of fusion is accompanied by an increase of entropy.
(ii) The entropy of vapourisation. It may be defined as the entropy change when one mole of the liquid changes into vapour at its boiling point.
       Liquid space rightwards harpoon over leftwards harpoon space space Gas
Mathematically comma space space space increment straight S subscript vap space equals space straight S subscript vap space minus space straight S subscript liq space equals space fraction numerator increment straight H subscript vap over denominator straight T subscript straight b end fraction
whereas space space increment straight S subscript vap space equals Entropy space of space vapourisation
space space space space space space space space space space space space space increment straight H subscript vap space equals space Enthalpy space of space vapourisation
space space space space space space space space space space space space space straight T subscript straight b space equals space Boiling space temperature space in space degree space kelvin.
Since ∆Hvap is +ve, therefore ∆Svap is +ve, hence the process of vapourisation is accompanied by an increase of entropy.