Question
State the thermodynamic conditions for spontaneous process to occur.
Solution
(i) For spontaneous process to occur ∆H < 0 (–ve)
(ii) ∆S of the process must be > 0 i.e. ∆S is +ve.
(iii) ∆G of the process must be < 0 i.e. ∆G is –ve.
