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Thermodynamics

Question
CBSEENCH11006192

Enthalpies of formation of CO(g), CO2(g), N2O(g) and N2O4 (g) are -110, -393, 81 and 9.7 kJ mol-1. Find the value of space increment subscript straight r straight H to the power of 0 for the reaction:
N2O4 (g) + 3CO(g)   space rightwards arrow  N2O(g) + 3CO2(g)

Solution
space increment subscript straight r straight H to the power of 0 space equals space sum from blank to blank of increment subscript straight f straight H to the power of 0 space left parenthesis Products right parenthesis space minus space sum from blank to blank of increment subscript straight f straight H to the power of 0 left parenthesis Reactants right parenthesis
space space equals open square brackets increment subscript straight f straight H to the power of 0 left parenthesis straight N subscript 2 straight O right parenthesis space plus 3 space cross times space increment subscript straight f straight H to the power of 0 left parenthesis CO subscript 2 right parenthesis close square brackets
space space space space space space space space space space space space space space space space space space space space space space space space space space space minus open square brackets increment subscript straight f straight H to the power of 0 left parenthesis straight N subscript 2 straight O subscript 4 right parenthesis space plus space 3 increment subscript straight f straight H to the power of 0 left parenthesis CO right parenthesis close square brackets
equals space left square bracket 81 plus 3 left parenthesis negative 393 right parenthesis right square bracket space minus space left square bracket 9.7 plus 3 left parenthesis negative 110 right parenthesis right square bracket
equals space 81 minus 1179 minus 9.7 plus 330
equals space minus 1188.7 plus 441 space equals space minus 777.7 space kJ