How much heat is evolved when 204g of ammonia are produced according to the equation,

$space straight N subscript 2 left parenthesis straight g right parenthesis space plus space 3 straight H subscript 2 left parenthesis straight g right parenthesis space rightwards arrow space space 2 NH subscript 3 left parenthesis straight g right parenthesis semicolon space increment straight H space equals space 92.6 space kJ$

Solution

2 mol i.e. 34 g of NH₃ produced are accompanied by the evolution of 92.6 kJ of heat.
So, 204 g of NH₃ produced would be accompanied by evolution of
$equals space fraction numerator 92.6 over denominator 34 end fraction cross times 204 space equals space 555.6 space kJ space heat$