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Thermodynamics

Question
CBSEENCH11006168

What mass of gold of specific heat capacity 0.13 J (°C)–1 g–1 can be heated through the same temperature difference when supplied with the same amount of energy as in (a) above?

Solution

We know that
                       space straight q space equals space straight c space cross times space straight m space cross times space increment straight T
or space space space space space space straight m space equals space fraction numerator straight q over denominator straight c cross times increment straight T end fraction space space space space space space space space space space space space space space space space.... left parenthesis 1 right parenthesis  
Here space straight c space equals space 0.13 space straight J left parenthesis degree straight C right parenthesis to the power of negative 1 end exponent straight g to the power of negative 1 end exponent semicolon space space space space increment straight T space equals space 475 degree straight C semicolon
space space space space space space space straight q space equals space 2.1 space cross times space 10 cubed straight J
Substituting the values in (1), we have,
        
space straight m space equals space fraction numerator 2.1 space cross times space 10 cubed straight J over denominator 0.13 straight J left parenthesis degree straight C right parenthesis to the power of negative 1 end exponent straight g to the power of negative 1 end exponent cross times left parenthesis 475 degree straight C right parenthesis end fraction
space space space space space equals space fraction numerator 2.1 space cross times space 10 cubed over denominator 0.13 space cross times space 475 end fraction straight g space equals space 34 space straight g